18m^2-12m-6=0

Solution for 18m^2-12m-6=0 equation:

18m^2-12m-6=0

a = 18; b = -12; c = -6;
Δ = b2-4ac
Δ = -122-4·18·(-6)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*18}=\frac{-12}{36}
=-1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*18}=\frac{36}{36}
=1
$